C++ function template two display reification

When using a structure as a formal parameter to assign a value to another structure, you only want to change the parameters of part of the structure content without changing all the parameters. You can use display reification.

For a given function name, there can be non-template functions, template functions, and display materialized template functions and their overloaded templates.

The prototype and definition of the display materialization should start with template<> and indicate the type by name.

Reification takes precedence over regular templates, and non-template functions take precedence over reification and regular templates.

The following are the non-template functions, template functions, and concrete prototypes used to exchange job structures:
 

//非模板函数原型

void swap(job &,job &);

//模板原型

template<typename T>

void swap(T &,T&);

//显示具体化

template<>void swap<job>(job &,job &);

demo example:

#include <QCoreApplication>
#include<QDebug>
#include<vector>
#include<iostream>
using namespace std;

template<typename T>
void swapData(T& a,T &b)
{
    T temp;
    temp = a;
    a = b;
    b = temp;
}
struct job
{
    char name[40];
    double salary;
    int floor;
};
//显示具体化
template<>void swapData<job>(job &j1,job &j2)
{
    double t1;
    int t2;
    t1 = j1.salary;
    j1.salary = j2.salary;
    j2.salary = t1;
    t2 = j1.floor;
    j1.floor = j2.floor;
    j2.floor = t2;

}
void show(job &j)
{
    cout<<"name: "<<j.name<<" salary: "<<j.salary<<" floor: "<<j.floor<<endl;
}

int main(int argc, char *argv[])
{
    QCoreApplication a(argc, argv);

    int i = 10,j=20;
    swapData(i,j);
    cout<<"\n";
    job sue = {"su",7000,2};
    job alice = {"alice",12121,3};
    show(sue);
    show(alice);
    swapData(sue,alice);
    cout<<"after switch ....";
    show(sue);
    show(alice);
    return a.exec();
}