[C ++] how to understand the function template [2] - the limitations of overloaded function template + template

table of Contents

Program example:

operation result:

Limitations template

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 Program example:

//twotemps.cpp -- 使用重载模板
#include<iostream>
template <typename T>
void Swap(T &a, T &b);

template <typename T>
void Swap(T *a, T *b, int n);

void Show(int a[]);
const int Lim = 8;
int main()
{
	using namespace std;
	int i = 10;
	int j = 20;
	cout << "i, j = " << i << ", " << j << ".\n";
	cout << "使用 int 的 Swapper： \n";
	Swap(i, j);
	cout << "Now i, j = " << i << ", " << j << ".\n\n";

	int d1[Lim] = { 0, 7, 0, 4, 1, 7, 7, 6 };
	int d2[Lim] = { 1, 2, 3, 4, 5, 6, 7, 8 };
	cout << "原始数组：\n";
	Show(d1);
	Show(d2);
	Swap(d1, d2, Lim);//匹配重载的另一个
	cout << "Swapped arrays:\n";
	Show(d1);
	Show(d2);
	return 0;
}

template <typename T>
void Swap(T &a, T &b)
{
	T temp;
	temp = a;
	a = b;
	b = temp;
}

template <typename T>
void Swap(T a[], T b[], int n)
{
	T temp;
	for (int i = 0; i < n; i++)
	{
		temp = a[i];
		a[i] = b[i];
		b[i] = temp;
	}
}

void Show(int a[])
{
	using namespace std;
	cout << a[0] << a[1] << "/";
	cout << a[2] << a[3] << "/";
	for (int i = 4; i < Lim; i++)
	{
		cout << a[i] ;
	}
	cout << endl;
}

operation result:

 

(8.12 program) 

Limitations template