[Ybt] [String processing class example 5] Same birthday

Same birthday

Topic link: Same birthday


Title description

Insert picture description here

Problem solving ideas

You can quickly sort multiple keywords.

code

#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<algorithm>
using namespace std;

int n,ok;

struct abc{
    
    
	string name;
	int m,d;
}a[100010];

bool cmp(abc a,abc b)
{
    
    
	if(a.m!=b.m)
		return a.m<b.m;
	if(a.d!=b.d)
		return a.d<b.d;
	if(a.name.size()!=b.name.size())
		return a.name.size()<b.name.size();
	return a.name<b.name;
}

int main()
{
    
    
	cin>>n;
	for(int i=1;i<=n;i++)
		cin>>a[i].name>>a[i].m>>a[i].d;
	sort(a+1,a+1+n,cmp);
	for(int i=1;i<=n;i++)
	{
    
    
		int j=i,s=0;
		while(a[j].m==a[i].m&&a[j].d==a[i].d)
			j++,s++;
		j--,s--;
		if(s>1)
		{
    
    
			ok=1;
			cout<<a[i].m<<" "<<a[i].d<<" ";
			for(int k=i;k<=j;k++)
				cout<<a[k].name<<" ";
			cout<<endl;
		}
		i=j;
	}
	if(!ok)
		printf("None");
}

Guess you like

Origin blog.csdn.net/SSL_guyixin/article/details/113004644