1.5 27: Sum of series

Description
Known: Sn = 1+1/2+1/3+...+1/n. Obviously for any integer K, when n is large enough, Sn is greater than K.

Now given an integer K (1<=k<=15), it is required to calculate a minimum n; making Sn>K.

Enter
an integer K.
Output
an integer n.
Sample input
1
Sample output
2

#include <iostream>
using namespace std;
int main()
{
    
    
	int k, n=1;
	double sum=0;
	cin>>k;
	while(1)
	{
    
    
		sum += (1.0)/n;
		if(sum > k)
		{
    
    
			break;
		} else
		{
    
    
			n++;
		}
	}
	cout<<n<<endl;
	return 0;
}