[Swift] LeetCode1191 K times the largest series of sub-arrays and |. K-Concatenation Maximum Sum

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Given an integer array arr and an integer k, modify the array by repeating it k times.

For example, if arr = [1, 2] and k = 3 then the modified array will be [1, 2, 1, 2, 1, 2].

Return the maximum sub-array sum in the modified array. Note that the length of the sub-array can be 0 and its sum in that case is 0.

As the answer can be very large, return the answer modulo 10^9 + 7.

 

Example 1:

Input: arr = [1,2], k = 3
Output: 9

Example 2:

Input: arr = [1,-2,1], k = 5
Output: 2

Example 3:

Input: arr = [-1,-2], k = 7
Output: 0

 

Constraints:

  • 1 <= arr.length <= 10^5
  • 1 <= k <= 10^5
  • -10^4 <= arr[i] <= 10^4

To give you an array of integers  arr and an integer  k.

First of all, we need to make changes to the array, that is, the original array  arr repeat  k times.

For instance, if  arr = [1, 2] and  k = 3, then after the array is modified  [1, 2, 1, 2, 1, 2].

Then, you return to the largest array of sub-arrays in the revised and.

Note that the length may be sub-arrays  0, its sum is also in this case  0.

As a result may be large, so it is necessary mode (mod)  10^9 + 7 and then return. 

 

Example 1:

Input: arr = [1,2], k = 3 
Output: 9

Example 2:

Input: arr = [1, -2,1] , k = 5 
Output: 2

Example 3:

Input: arr = [-1, -2] , k = 7 
Output: 0

 

prompt:

  • 1 <= arr.length <= 10^5
  • 1 <= k <= 10^5
  • -10^4 <= arr[i] <= 10^4

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Origin www.cnblogs.com/strengthen/p/11521662.html