This question requires the realization of two functions: one function judges whether the sum of the digits of a given positive integer is equal to 5; the other function counts how many integers meet the above requirements in a given interval, and calculates the sum of these integers.
Function interface definition:
int is( int number );
void count_sum( int a, int b ); The
function is judges whether the sum of the digits of number is equal to 5, if yes, it returns 1, otherwise it returns 0.
The function count_sum uses the function is to count how many integers in a given interval [a, b] meet the above requirements (that is, let is return 1), and calculate the sum of these integers. Finally follow the format
count = the number of integers that meet the condition, sum = the sum of these integers and
output. The question is guaranteed to be 0<a≤b≤10000.
Sample referee test procedure:
#include <stdio.h>
int is( int number );
void count_sum( int a, int b );
int main()
{
int a, b;
scanf("%d %d", &a, &b);
if (is(a)) printf("%d is counted.\n", a);
if (is(b)) printf("%d is counted.\n", b);
count_sum(a, b);
return 0;
}
/* 你的代码将被嵌在这里 */
Input sample:
104 999
Output sample:
104 is counted.
count = 15, sum = 3720
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int is(int number)
{
int sum = number % 10;
do
{
number /= 10;
sum += number % 10;
}while (number / 10 > 0);
if (sum == 5)
return 1;
else
return 0;
}
void count_sum(int a, int b)
{
int count, sum;
count = sum = 0;
for (int i = a; i <= b; i++)
if (is(i))
{
count++;
sum += i;
}
printf("count = %d, sum = %d", count, sum);
}