Count the number of times each character appears in a sentence

Claim:

Calculating a number of occurrences of each character string.
Experience: As used herein HashMap <K, V> advantage is that there will hashMap will automatically remove duplicate key

1. Obtain a string object
2. Create a Map collection of key representative character, the value represents the number of times.
3. traversal strings to get each character.
4 determines whether the key Map.
5. If not, the first time, stores a number of times; if so, description has occurred, the corresponding values acquired ++ stored again.
6. Print the final results

Code:

 1 import java.util.HashMap;
 2 import java.util.Scanner;
 3 
 4 public class MapTest {
 5     public static void main(String[] args) {
 6         Scanner input = new Scanner(System.in);
 7         String str = input.nextLine();
 8         HashMap<Character, Integer> hashMap = new HashMap<>();
 9         for(int i = 0;i < str.length();i ++){
10             char c = str.charAt(i);
11             IF (! hashMap.containsKey (C)) {
 12 is                  hashMap.put (C,. 1 );
 13 is              }
 14              the else {
 15                  // public V GET (Object Key), acquires a value corresponding to the set in Map with a specified key. 
16                  Integer COUNT = HashMap.get (C);
 . 17                  hashMap.put (C, COUNT ++); // not be used here ++ COUNT 
18 is  
. 19              }
 20 is          }
 21 is          System.out.println (hashMap ');
 22 is      }
 23 is }