[ERROR] note of the low-level errors committed by using time package today.

Use time when the package

func (t Time) Add(d Duration) Time 我希望实现Add自定义时间

	now := time.Now()
	now.Add(8*time.Second)

　　

In the normal use, we are using the time and a literal integer multiplied time interval type.

 

I hope to do so

func SetOverdueTime (s int){
	t  := time.Now()
	t.Add(s*time.Second)

　　Austria has been an error, because the variable s and time.Second are two different types can not be multiplied. But can be directly multiplied by the literal is 8 * time.Second, the same value as a literal and the type of underlying multiply the result after denomination or type.

So Solution

func  SetOverdueTime (s int){
        t := time.Now()
	t.Add(time.Duration(s)*time.Second)

　　Do a cast on it. =. = Very low but still think we should remember this.

 Here is the verification

	a := 8
	if 8*time.Second == time.Duration(a)*time.Second{
		fmt.Printf("一样哒~")
	}