Interview questions - function prototypes

Question about function prototype:

	function Foo(){
		getName = function(){
			console.log(1)
		}
		return this;
	}
	
	Foo.getName = function(){
		console.log(2)
	}
	
	Foo.prototype.getName = function(){
		console.log(3)
	}
	
	var getName = function(){
		console.log(4)
	}
	
	function getName(){
		console.log(5)
	}
	
	Foo.getName();
	getName();
	Foo().getName();
	getName();
	new Foo.getName();
	new Foo().getName();
	new new Foo().getName();

Analysis: var presence and anonymous functions to variable lift code execution is lifted to the top of the following functions;

getName = function(){
	console.log(5)
}

Function is executed

1. Foo getName method of performing an output;

	Foo.getName() // 2；

2. Is performed var getName = ... will function to enhance the coverage;

	getName() // 4

3. After performing the function and cover getName Foo, then call getName function, then the function call getName;

	Foo().getName() // 1

4. Performing getName () function is a step function is performed on the case;

	getName() // 1

5. This function is performed investigation operator precedence ;

	new Foo.getName() // => new (Foo.getName)()  输出 2；

6. This function performs the same inspection operator precedence , but this time the new new Foo () is executed example Foo Foo instance because there is no method getName, you will find the prototype to protoType;

	new Foo().getName() // => (new Foo()).getName() 输出 3

7. This function performs the same inspection operator precedence , the first two are integrated;

new new Foo().getName() // => new ((new Foo()).getName)() // 3