[C language] to enter a three-digit number, reverse output

Code 1:

#include<stdio.h>
int main()
{
    you work; you y; you are a, b, c;
    printf ( " Please enter a three-digit number: " );
    scanf_s("%d",&x);
    a=x/100;
    b=x/10%10;
    c=x%10;
    and = 100 * c + 10 * b + a;
    the printf ( " reverse output D% \ n- " , Y);
}

Code 2:

#include<stdio.h>
int main()
{
    int m, n;
    printf ( " Please enter a three-digit integer: \ the n- " );
    scanf_s("%d", &m);
    n- = m% 10 * 100 + m / 10 % 10 * 10 + m / 100 ; // to the bits, ten, one hundred multiplied by the corresponding number of bits obtained by adding 
    the printf ( " reverse output% d \ the n- " , the n-);
    
}

Code 3:

#include<stdio.h>
int main()
{
    int x;
    printf ( " Please enter a three-digit number: " );
    scanf_s("%d", &x);
    the printf ( " reverse output D% D% D% \ n- " ,% X 10 , X / 10 % 10 , X / 100 );
     return  0 ;
}

 

result:

 

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Origin www.cnblogs.com/HGNET/p/12619317.html