ピーター・サンルーフ:
誰の助けに私は私の問題を解決するためにできますか?現在、私は成功した写真や機能をアップロードすることができ、システムを作成しました。しかし、データベースにしても、サーバのフォルダに保存した写真の名前は、写真の実際の名前です。
今、私はIDに基づいて、写真の名前を変更したいです。以下は、私のコードは次のようになります。
<?php
require_once '../../../../config/configPDO.php';
$report_id = $_POST['report_id'];
$image = $_FILES['uploadFile']['name'];
// image file directory
$target = "../../../../images/upload/".basename($image);
$ServerURL = "http://172.20.0.45/tgotworker_testing/images/upload/$image";
// Prepare an insert statement
$query = "UPDATE ot_report SET photo_before = '$ServerURL', time_photo_before = GETDATE() WHERE report_id = :report_id";
$sql = $conn->prepare($query);
$sql->bindParam(':report_id', $report_id);
$sql->execute();
// Attempt to execute the prepared statement
if($sql&&move_uploaded_file($_FILES['uploadFile']['tmp_name'], $target)){
// Records created successfully. Redirect to landing page
echo "<script>alert('Saved')</script>";
header("Location: view_task.php?report_id=".$_POST['report_id']);
exit();
} else{
echo "Something went wrong. Please try again later.";
}
?>
Tushar:
このコードを試してみてください
require_once '../../../../config/configPDO.php';
$report_id = $_POST['report_id'];
$image = $_FILES['uploadFile']['name'];
//set new name for upload image
$temp = explode(".", $_FILES["file"]["name"]);
$newfilename = $report_id. '.' . end($temp);
$target = "../../../../images/upload/".$newfilename;
$ServerURL = "http://172.20.0.45/tgotworker_testing/images/upload/$newfilename";
// Prepare an insert statement
$query = "UPDATE ot_report SET photo_before = '$ServerURL', time_photo_before = GETDATE() WHERE report_id = :report_id";
$sql = $conn->prepare($query);
$sql->bindParam(':report_id', $report_id);
$sql->execute();
// Attempt to execute the prepared statement
if($sql&&move_uploaded_file($_FILES['uploadFile']['tmp_name'], $target)){
// Records created successfully. Redirect to landing page
echo "<script>alert('Saved')</script>";
header("Location: view_task.php?report_id=".$_POST['report_id']);
exit();
} else{
echo "Something went wrong. Please try again later.";
}
?>