C programming experiment REPORT
Name: Zhou Manjie
experiment Location: Home
Lab time: 2020.03.12
A purpose and requirements of the experiment
1, master ++ increment, decrement - proper use of operators.
2, the basic control functions of the basic input / output functions, call the method, an input / output control of a predetermined format and the like.
3, the means to acquire the algorithm described structural program
4, C language proficiency of the operator, i.e., operator precedence and tuberculosis, operation rule, type of operands.
II. Experimental content
1, lab exercises: 2.3.3 and ASCII character code
A brief description of the problem: None
2 experiment code:
#include<stdio.h>
main()
{
int a,b,c,d;
printf("请输入一个大写字母:\n");
scanf("%c",&a);
b=a+32;
c=b-1;
d=b+1;
printf("小写字母为:%c,%C,%C\n",c,b,d);
printf("ASCII码的值为:%d,%d,%d",c,b,d);
}Analysis 3: Note (a difference of 32 between uppercase and lowercase letters)
2, exercises: Application 2.3.4 Operators and expressions
A brief description of the problem: the use of rounded and take the remainder
2 experiment code:
#include<stdio.h>
main()
{
int a,b,c,x,y;
printf("请输入一个三位数的整数：\n");
scanf("%d",&x);
a=x/100;
b=x%100/10;
c=x%10;
y=c*100+b*10+a;
printf("%d:%d\n",x,y);
return 0;
}3 Analysis: Note the use of% /.
3. exercises: 2.3.5 sequential structure of the application
A brief description of the problem: the input switch
2 experiment code:
#include<stdio.h>
main()
{
float a,b,c,d,x,y,z,m,n; /*a表示西药费，b表示检查费，c表示材料费，d表示床位费，x表示观察费，y表示护理费，z表示病人所付款数，m表示应付款数，n表示应找回金额*/
printf("请输入西药费，检查费，材料费，床位费，观察费，护理费:\n");
scanf("%f,%f,%f,%f,%f,%f",&a,&b,&c,&d,&x,&y);
m=a+b+c+d+x+y;
printf("应付款数（元）:%.2f",m);
printf("病人付款（元）：");
scanf("%f",&z);
n=z-m;
printf("计算结果:");
printf("病人付款=%6.2f元\n应收款=%6.2f元,应找回=%6.2f元\n",z,m,n);
return 0;
}Analysis 3: Enter a comma after the word need to switch text input
4. exercises: Algorithms 3.3.1 mathematical functions
A brief description of the problem: None
2 experiment code:
#include<stdio.h>
main()
{
float x,y;
printf("请输入x的值:");
scanf("%f",&x);
if(x<1)y=x;
else if (1<x&&x<10)y=2*x-1;
else if(x>10)
y=3*x-1;
printf("y的值域为%.2f\n",y);
}Analysis 3: None
4 is a flowchart:
5. exercises: 3.3.2 Algorithm Description chickens and rabbits with cage
A brief description of the problem: the need for a custom variable integer
2 experiment code:
#include<stdio.h>
main()
{
int h,f,x,y;
printf("鸡和兔的总数，鸡和兔脚的总数：");
scanf("%d,%d",h,f);
if(h>0&&f>0)
{
x=(4*h-f)/2;
y=(f-2*h)/2;
printf("鸡有%d只 兔有%d只\n",x,y);
}
else
{
printf("数值错误！\n");
}
return 0;
}Analysis 3: Numerical error conditions exist
4 Flowchart:
6. exercises: 3.3.3 to determine the coordinates of the algorithm description
A brief description of the problem: a float
2 experiment code:
#include<stdio.h>
#include<math.h>
main()
{
int h=10;
float x1=1,y1=2,x2=-2,x3=-2,y2=2,y3=-2,x4=2,y4=-2,x,y,d1,d2,d3,d4;
printf("请输入一个(x,y):");
scanf("%f,%f",&x,&y);
d1=sqrt((x-x1)*(x-x1)+(y-y1)*(y-y1));
d2=sqrt((x-x2)*(x-x2)+(y-y2)*(y-y2));
d3=sqrt((x-x3)*(x-x3)+(y-y3)*(y-y3));
d4=sqrt((x-x4)*(x-x4)+(y-y4)*(y-y4));
if(d1>1&&d2>1&&d3>1&&d4>1)
h=0;
else h=10;
printf("该塔的高度为%d",h);
}3 Analysis: need to be defined separately for each variable, and use the function.
Experiments Summary
In this experiment, the use MACKDOWN learned, and added thereto a flowchart there have been some problems, for example, in the English input switching, etc., is also familiar with the use of the function.