Address original title: https://leetcode-cn.com/problems/permutations/
Description Title:
Given a sequence of numbers is not repeated, all possible return to full permutation.
Example:
Input: [1,2,3]
Output:
[
[1,2,3],
[1,3,2],
[2,1,3],
[2,3,1],
[3,1 , 2],
[3,2,1]
]
Problem-solving programs:
[46] LeetCode full array (C ++)
One year later, it becomes difficult to write back ioi had a lot to say how simple this is nonsense ...
Code:
class Solution {
List<List<Integer>> res;
public List<List<Integer>> permute(int[] nums) {
res = new ArrayList<>();
List<Integer> ans = new ArrayList<>();
boolean[] visited = new boolean[nums.length];
backtrack(visited, nums, ans);
return res;
}
public void backtrack(boolean[] visited, int[] nums, List<Integer> ans)
{
int n = nums.length;
if(ans.size() == n)
res.add(new ArrayList(ans));
for(int i = 0; i < n; i ++)
{
if(visited[i] == false)
{
visited[i] = true;
ans.add(nums[i]);
backtrack(visited, nums, ans);
ans.remove(ans.size() - 1);
visited[i] = false;
}
}
}
}