java launch the default browser, and to pass multiple parameters problem

java start the browser many ways, I am also referring to the summary of the god on the basis of you, want to help other students, thanks to big brother

https://blog.csdn.net/zp357252539/article/details/77896257/ , there is talk of launching a browser many ways, but the pass parameters to die,

		try {
					
					
					 Runtime.getRuntime().exec( "cmd   /c   start   http://localhost:8012/admin/sysAdminOfPlatform.do?sysId=141);
				
				} catch (IOException e) {
					// TODO Auto-generated catch block
					e.printStackTrace();
				}

This approach can only pass a parameter, controller background with String id = request.getParameter ( "sysId"); receiving, but then I found that you can pass multiple parameters-place, and start the default browser

try {
				//http://localhost:8012
				String serverName=request.getServerName();
				int port=request.getServerPort();

				String url = "http://"+serverName+":"+port+"/admin/sysAdminOfPlatform.do?sysId=141&uesrId=1681&memberid="+m.getId();
				java.net.URI uri = java.net.URI.create(url);
				// 获取当前系统桌面扩展
				java.awt.Desktop dp = java.awt.Desktop.getDesktop();
				// 判断系统桌面是否支持要执行的功能
				if (dp.isSupported(java.awt.Desktop.Action.BROWSE)) {
					dp.browse(uri);
					// 获取系统默认浏览器打开链接
				}
			} catch (java.lang.NullPointerException e1) {
				// 此为uri为空时抛出异常
				e1.printStackTrace();
			} catch (java.io.IOException e1) {
				// 此为无法获取系统默认浏览器
				e1.printStackTrace();
			}

Eradicate address, a plurality of transmission parameters, the following background reception

Integer sysId=Integer.valueOf(request.getParameter("sysId"));
Integer userId=Integer.valueOf(request.getParameter("uesrId"));
Integer memberid=Integer.valueOf(request.getParameter("memberid"));

The perfect solution!