Title Description
Finding a small number of array K, the same attention as large as the size of the operator
as 213,452 third decimal 3 as
in (parentheses is a comment)
input:
6 (array length n-)
2. 5. 1 3 2 2 ( array)
3 (K is the third decimal)
output:
3
Analysis: The first element and then sorted according to pre judge whether the current comparison of the same
void find_k()
{
int n;
cin >> n;
vector<int> nums;
if (n == 0)
{
return;
}
int t;
for (int i = 0; i < n; i++)
{
cin >> t;
nums.push_back(t);
}
sort(nums.begin(), nums.end());
int k;
cin >> k;
t = 1;
int i = 1;
int pre = nums[0];
while (i < nums.size() && t < k)
{
if (pre != nums[i])
{
t++;
pre = nums[i];
}
i++;
}
if (t == k)
{
cout << nums[i - 1] << endl;
}
else
{
cout << 0 << endl;
}
}