description
Given a list that each element is either a list or an integer. Turning it into a simple list containing only integers.
If the elements of a given list is itself a list, then it can also contain lists.
Sample
样例 1:
输入: [[1,1],2,[1,1]]
输出:[1,1,2,1,1]
样例解释:
将其变成一个只包含整数的简单列表。
样例 2:
输入: [1,2,[1,2]]
输出:[1,2,1,2]
样例解释:
将其变成一个只包含整数的简单列表。
样例 3:
输入:[4,[3,[2,[1]]]]
输出:[4,3,2,1]
样例解释:
将其变成一个只包含整数的简单列表。
Although this topic is classified as simple, I thought to themselves to see addressed outgoing interface specific method yet. Harm, which Zhenshi Ben.
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
*
* // @return true if this NestedInteger holds a single integer,
* // rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds,
* // if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // @return the nested list that this NestedInteger holds,
* // if it holds a nested list
* // Return null if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
public class Solution {
public static void diGui(List<Integer> result, List<NestedInteger> nestedInteger) {
for(int len = 0;len<nestedInteger.size();len++){
NestedInteger param = nestedInteger.get(len);
if (param.isInteger()) {
result.add(param.getInteger());
} else {
diGui(result, param.getList());
}
}
}
public static List<Integer> flatten(List<NestedInteger> nestedList) {
// Write your code here
List<Integer> result = new ArrayList<>();
diGui(result, nestedList);
return result;
}
}
