1083 List Grades (25分)

Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade’s interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student’s name and ID, separated by one space. If there is no student’s grade in that interval, output NONE instead.

Sample Input 1:

4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100

Sample Output 1:

Mike CS991301
Mary EE990830
Joe Math990112

Sample Input 2:

2
Jean AA980920 60
Ann CS01 80
90 95

Sample Output 2:

NONE

Sorting structure

Source:

#include<bits/stdc++.h>
using namespace std;
typedef struct student{
    string name;
    string id;
    int score;
}stu;
bool compare(stu a,stu b)
{
    return a.score>b.score;
}
int main()
{
    int n;cin>>n;
    stu a[n];
    for(int i=0;i<n;i++)
    cin>>a[i].name>>a[i].id>>a[i].score;
    sort(a,a+n,compare);
    int floor,ceil;
    cin>>floor>>ceil;

    int f=1;
    for(int i=0;i<n;i++)
    {
        if(a[i].score>=floor&&a[i].score<=ceil)
        {
            f=0;
            cout<<a[i].name<<" "<<a[i].id<<endl;
        }
    }
    if(f)
        cout<<"NONE"<<endl;
}