Testing continue play a role in whether the switch-case

for(i=0,j=0; i<4; i++)

{

    switch(i)

    {

        case 0: j ++;

                      break;

        case 1: continue;

                       j++;

                       break;

        default: break;

    }

    printf("j=d%\n",j);

}

If you do not work continue, it should print four results, j final two.

j=1

j=2

j=2

j=2

If the continue function, the results should be printed three final value 1 and j.

j=1

j=1

j=1

 

Vs platform should verify, print the results for the latter to prove that continue switch-case in the cycle played a role.