[07] python learning system to read a map and learn how to operate dictionary

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Data Types - Dictionary (dict)

table of Contents:

Get a picture dictionary

A little knowledge points get a picture dictionary 字典知识点脑图

If the knowledge described in the figure too general, see the following fine text:

What is the dictionary

js object

When it comes to the dictionary, front-end students can understand it as: object. Because the object of long python and js in the dictionary can not say like, it is simply the same.

Dictionary is a collection of key-value pairs to more than one to one child elements.

It is the same list, just as a data type of complex.

Wherein the key name in the dictionary must be a string type, and the value corresponding to the keys may be of any type.

Dictionary long-sawed

Having said that, the dictionary in the end sawed? Unveiled:

Pseudo-code syntax

列表变量名 = {
  '字符串键名key1': 对应key1的值value1, 
  '字符串键名key2': 对应key2的值value2, 
  ...(更多key、value对儿)
}

Examples demo

A dictionary definition of the demo code, you can pay attention to the next, the next case might be used.

dictName = {
  'name': '小石头',
  'age': 19,
  'hobby': {
    'it': ['css','js','python'],
    'daily': [['music','tv'],['apple','pear']],
    'sports': 'sleep'
  },
  'married': True
}

Syntax imaging

By pseudo-code and demo code that we can conclude the following characteristic points on the dictionary:

  • Custom variable names

  • The dictionary assigned to the variable equal sign (dictName)

  • The right of the equal sign is a dictionary, with a child wrapped in one pair of braces

  • Internal dictionary is a pair of key-value pair (key: key; Found: value).

  • 键名 scripts welfare

    • That is the key name must be wrapped in quotes, otherwise it will error
    • Error type: NameError variable undefined error
  • Key names are not the only need to repeat

    • Above, dictName, the only one "age"
    • If there are multiple keys with the same name, leaving only the last key
    keyNameOnly = {
      'age': 29,
      'age': 19,
      'name': '小石头'
    }
    print(keyNameOnly) 
    # {'age': 19, 'name': '小石头'} age对应29的键值对被覆盖了
    
  • Value can be any type of value

  • A target value of the content may be repeated

      valueNameRepeat = {
        'name': '小石头',
        'like': '小石头',
        'realTalk': True
      }
      print(valueNameRepeat)
      # {'name': '小石头', 'like': '小石头', 'realTalk': True} 值‘小石头’重复也无所谓。
    
  • Colon connection between the key identifier and the value

  • Key (key) combined value (value) is formed with a pair of keys, called child

  • Each pair of children between the keys on separated by commas

  • Dictionary can have any number of key-value pairs children

  • The last key-value pairs of children do not need a comma

How to use the dictionary

Get the length of the dictionary function --len

我们可以用len()函数来得出一个列表或者字典的长度(元素个数)

括号里放列表或字典名称

print(len(dictName))  #4,因为又4对儿,键名分别是name、age、hobby和married

列表的长度也是用len()函数获取

提取字典中的元素

通过字典的索引(键名)来获取对应的值

伪代码:

字典名[字典的键]

字典没有偏移量,所以中括号写的是键名

demo:

dictName['name'] # 小石头

嵌套提取

拓展 - 二维嵌套列表值的提取方法

同样是用偏移量来获取。

listdemo = [['music','tv'],['apple','pear']]
print(listdemo[1][1]) # pear

先用第一个偏移量获取最外边列表的第1个元素。得到列表['apple','pear']后,再继续追加一个偏移量[1]获取得到的列表['apple','pear']中第一个元素,打印出'pear'

拓展 - 多维嵌套字典中值的提取方法

因为是用键名,而不是偏移量的方法获取。所以感觉在理解逻辑上,比列表容易让初学者接受。

print(dictName['hobby']['sports']) # sleep

先用键名"hobby"获取其对应的值,再用“hobby”里的"sports"获取其sports自己对应的值。得到"sleep"

拓展 - 列表与字典互相嵌套时值的提取方法

举一反三,概念加强版

print(dictName['hobby']['daily'][0][0]) # music

往字典中增加元素

新增键值对要用到赋值语句 伪代码:

字典名[键] = 值

自我感觉很好理解。只需要在提取的基础上赋值即可。

⚠️但可能需要注意,如果键名是字典中已经存在的,再这么操作就会直接修改这个键的值。

示例代码:

dictName['homeland'] = 'china'
print(dictName)

删除字典中的元素

删除字典里键值对的代码是del语句

伪代码:

del 字典名[键]

示例代码:

del(dictName['married'])
print(dictName)

对比列表的异同

相同点

1、修改值时都是通过赋值:在列表和字典中,如果要修改元素,都可用赋值语句来完成

2、值类型支持任意嵌套:除基本数据类型外,列表可嵌套其他列表和字典,字典也可嵌套其他字典和列表。

不同点

1、比较相等时规则不同

列表中的元素是有自己明确的“位置”的,所以即使看似相同的元素,只要在列表所处的位置不同,它们就是两个不同的列表

而字典中的数据是随机排列的,所以相比时即使键调动顺序也不影响

代码观察:


students1 = ['小明','小红','小刚']
students2 = ['小明','小红','小刚']
print(students1 == students2) 
# True 必须元素顺序、个数、内容皆一致则相同

students3 = ['小明','小红','小刚']
students4 = ['小明','小刚','小红']
print(students3 == students4) 
# False 改变了一下顺序就不相等了


scores1 = {'小明':95,'小红':90,'小刚':100}
scores2 = {'小刚':100,'小明':95,'小红':90}
print(scores1 == scores2) 
# True 只要两个字典中,键名及其分别对应的值都一一相等,则整个字典相等。

scores3 = {'小明':95,'小红':90,'小刚':100}
scores4 = {'小明':9,'小红':90,'小刚':100}
print(scores3 == scores4) 
# False 这样,即使键名一一对应,键名所对应的值不同,最终结果不相等。

2、读取数据的方法不同

列表有序,要用偏移量定位

字典无序,可通过唯一的键来取值

观察代码:


# 提取列表中的数据 - 用偏移量/索引/下标
listdemo = ['apple','pear']
print(listdemo[1]) # pear

# 提取字典中的数据 - 用键名
keyNameOnly = {
  'age': 29,
  'age': 19,
  'name': '小石头'
}
print(keyNameOnly['age']) # 19

练习题

you = {
  'name': '',
  'a': [{
    'b': {
      'c': '强撑',
      'love': 'anybody'
    }
  }],
  'age': 30
}

4、在b里边增加爱好,为一个数组,数组内容自定
3、删除“age”
2、修改“name”的值
1、提取出“love”的值

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Origin www.cnblogs.com/padding1015/p/12232571.html