"24 network flow problem" round table dinner

Network flow problems, a detailed look at the code

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 
 4 int n,m,tot=-1,h[3005],ans=0,sum=0;
 5 struct node{
 6     int from,next,to,rest,full;
 7     int last;
 8 }e[100005];
 9 void add(int x,int y,int z){
10     tot++;
11     e[tot].next=h[x];
12     h[x]=tot;
13     e[tot].from=x;
14     e[tot].to=y;
15     e[tot].rest=z;
16     e[tot].full=z;
17 }
18 
19 int dis[3005],g[3005],flow[3005];
20 bool vis[3005];
21 
22 int bfs(int s,int t){
23     queue<int>q;
24     dis[s]=0;
25     q.push(s);vis[s]=true;
26     while(!q.empty()){
27         int u=q.front();vis[u]=false;q.pop();
28         for(int i=h[u];i!=(-1);i=e[i].next){
29             if(dis[e[i].to]>dis[u]+1&&g[e[i].to]==(-1)&&e[i].rest>0){
30                 g[e[i].to]=i;
31                 flow[e[i].to]=min(flow[u],e[i].rest);
32                 dis[e[i].to]=dis[u]+1;
33                 if(vis[e[i].to]==false){
34                     vis[e[i].to]=true;
35                     q.push(e[i].to);
36                 }
37             }
38         }
39     }
40 }
41 
42 int EK(int s,int t){
43     while(1){
44         memset(vis,false,sizeof(vis));
45         memset(dis,0x7f,sizeof(dis));
46         memset(flow,0x7f,sizeof(flow));
47         memset(g,-1,sizeof(g));
48         bfs(s,t);
49         if(g[t]==(-1))return 0;
50         ans+=flow[t];
51         for(int p=t;p!=(s);p=e[g[p]].from){
52             e[g[p]].rest-=flow[t];
53             e[g[p]^1].rest+=flow[t];
54         }    
55         
56     }
57 }
58 
59 int main(){
60     memset(h,-1,sizeof(h));
61     cin>>m>>n;
62     for(int i=1;i<=m;i++){
63         int co;cin>>co;sum+=co;
64         add(0,i,co);
65         add(i,0,0);
66         for(int j=1;j<=n;j++){
67             add(i,j+m,1);
68             add(j+m,i,0);
69         }
70     }
71     for(int i=1;i<=n;i++){
72         int co;cin>>co;
73         add(i+m,n+m+1,co);
74         add(n+m+1,i+m,0);
75     }
76     EK(0,n+m+1);
77     if(sum>ans){
78         cout<<0<<endl;
79         exit(0);
80     }
81     cout<<1<<endl;
82     for(int i=1;i<=m;i++){
83         for(int j=h[i];j!=(-1);j=e[j].next){
84             if(e[j].to!=0&&e[j].rest==0){
85                 cout<<e[j].to-m<<" ";
86             }
87         }
88         cout<<endl;
89     }
90 }
View Code

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Origin www.cnblogs.com/shatianming/p/12227600.html