5. The graphical output

1.A1031

#include<stdio.h> 
#include<string.h>
int main(){
	char str[100]; 
	gets(str);
	int N = strlen(str);
	int n1 = (N+2)/3,n3 = n1,n2 = N+2-n1-n3;
	for(int i = 0;i<n1-1;i++){
		printf("%c",str[i]);
		for(int j = 0;j<n2-2;j++)
			printf(" ");
		printf("%c\n",str[N-i-1]);
	} 
	for(int i = 0;i<n2;i++){
		printf("%c",str[n1+i-1]); 
	}
	return 0;
}

2.B1027

#include<stdio.h> 
#include<math.h>
int main(){
	int n;
	char c;
	scanf("%d %c",&n,&c);
	int bottom = (int)sqrt(2.0*(n+1)) - 1;	//最长边拥有的字符数 
	if(bottom%2==0)	bottom-=1;
	int used = (bottom+1)*(bottom+1)/2-1;	//使用的字符总数 
	
	//倒三角
	for(int i = bottom;i>=1;i-=2){
		for(int j = 0;j<(bottom-i)/2;j++)
			printf(" "); 
		for(int j = 0;j<i;j++)
			printf("%c",c);
		printf("\n"); 
	}
	
	//正三角 
	for(int i = 3;i<=bottom;i+=2){
		for(int j = 0;j<(bottom-i)/2;j++)
			printf(" "); 
		for(int j = 0;j<i;j++)
			printf("%c",c);
		printf("\n"); 
	}
	printf("%d\n",n-used);
	return 0;
}

3.B1036

#include<stdio.h> 
int main(){
	int row,col;
	char c;
	scanf("%d %c",&col,&c);
	if(col%2 == 1)	row = col/2+1;
	else	row = col/2;
	for(int i = 0;i<col;i++)
		printf("%c",c);
	printf("\n");
	for(int i = 2;i<row;i++){
		printf("%c",c);
		for(int j = 0;j<col-2;j++)
			printf(" ");
		printf("%c\n",c);	
	}
	for(int i = 0;i<col;i++)
		printf("%c",c);
	return 0;
}