Group Programming ladder match L2-005 set of similarity (25 points)

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L2-005 set of similarity (25 points)

thinking:

which means asking two sets title;
first set of A, B, respectively, de-emphasis, that is the answer n in m ( A B ) / n in m ( A B ) num(A\bigcap B)/num(A\bigcup B)

Code:

#include<bits/stdc++.h>

using namespace std;

const int maxn = 55;
vector<int> v[maxn];
int cnt[maxn];

inline void solve(int & x, int & y){
	vector<int> ans = v[x];
	for(int i = 0; i < cnt[y]; ++i)	ans.push_back(v[y][i]);
	sort(ans.begin(), ans.end());
	int nt = unique(ans.begin(), ans.end()) - ans.begin();
	printf("%.2f%%\n", 100.0 * (cnt[x] + cnt[y] - nt) / nt);
}

int main() {
#ifdef MyTest
	freopen("Sakura.txt", "r", stdin);
#endif	
	int n, k;
	scanf("%d", &n);
	for(int i = 1; i <= n; ++i){
		int m;
		scanf("%d", &m);
		v[i].resize(m);
		for(int j = 0; j < m; ++j) scanf("%d", &v[i][j]);
		sort(v[i].begin(), v[i].end());
		cnt[i] = unique(v[i].begin(), v[i].end()) - v[i].begin();
	}
	scanf("%d", &k);
	while(k--){
		int x, y;
		scanf("%d %d", &x, &y);
		solve(x, y);
	}
	return 0;
}
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Origin blog.csdn.net/qq_45228537/article/details/104033917