python regular expression matching IP

import re

re.search(r'([1]\d\d|2[0-4]\d|25[0-5])','192')


#re.search(r'([01]\d\d)','1XX') 
#[01]    \d       \d
# 1      0-9      0-9

#re.search(r'(2[0-4]\d)','2XX') 
#2     [0-4]       \d
#2      0-4        0-9

#re.search(r'(25[0-5])','25X')
#25   [0-5]  
#25    0-5

re.search(r'(([01]{0,1}\d{0,1}\d|2[0-4]\d|25[0-5])\.){3}([01]{0,1}\d{0,1}\d|2[0-4]\d|25[0-5])','192.168.103.114')
 # {} Repeat blanket: repeated 3 times {3}; {0,1} was repeated once or twice

Note: 255.255.255.255 broadcast address; 0.0.0.0 reserved addresses

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Origin www.cnblogs.com/moongo/p/12099212.html