Recursive solve the problem - a maze

The idea is to use a recursive loop judge found the path to the exit of

public class MiGong {
    public static void main(String[] args) {
        //地图
        int[][] map = new int[8][7];
        //
        for (int i = 0; i < 7; i++) {
            map[0][i] = 1;
            map[7][i] = 1;
        }
        for (int i = 1; i < 8; i++) {
            map[i][0] = 1;
            map[i][6] = 1;
        }
        map[3][1] = 1;
        map[3][2] = 1;
        map[1][2] = 1;
        map[2][2] = 1;
        //输出地图
        for (int i = 0; i < 8; i++) {
            for (int j = 0; j < 7; j++) {
                System.out.print(map[i][j]+" ");
            }
            System.out.println();
        }
        System.out.println();
        // recursive backtracking to find a way 
        setWay (Map,. 1,. 1 );
         for ( int I = 0; I <. 8; I ++ ) {
             for ( int J = 0; J <. 7; J ++ ) {
                System.out.print(map[i][j]+" ");
            }
            System.out.println();
        }
    }

    // 0 through 1 represents no wall 2 shows can go through 3 represent a dead end

    / ** 
     * @param the Map Map
     * @Param I starting position
     * @param j
     * @Return found otherwise returns true to false
      * / 
    public  static  Boolean setWay ( int [] [] Map, int I, int J) {
         IF (Map [. 6] [. 5] == 2 ) {
             return  true ;
        } else {
            if (map[i][j] == 0) {
                map[i][j] = 2;
                if (setWay(map, i + 1, j)) {
                    return true;
                } else if (setWay(map, i, j + 1)) {
                    return true;
                } else if (setWay(map, i - 1, j)) {
                    return true;
                } else if (setWay(map, i, j - 1)) {
                    return true;
                } else {
                    map[i][j] = 3;
                    return false;
                }
            } else {
                return false;
            }
        }
    }
}

Guess you like

Origin www.cnblogs.com/bingbug/p/12090914.html