8 Python basis of interview exercises

1.26 pairs capitalization printing, for example: Aa, Bb ......

 for i in range(26):
     print(chr(65+i)+chr(97+i))

2. A list contains 10 digits, and generates a new list, the new list number which requires number than before over

'''
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'''
 list=[2,3,6,4,7,5,1,8,9,0]
 list1=[]
 for i in list:
     list1.append(i+1)
 print(list1)

3. Remove the descending first letter of each word, such as: I am a good boy!
method 1

tre='I am a good boy！'
t=tre.split()
#print(t)
t.reverse()
list=[]
#print(t)
for i in t:
    list.append(i[0])
print(list)

Method 2

'''
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'''
a = "I AM A BOY"
result = []
for i in a.split()[::-1]:
    result.append(i[0])
print(result)

4. Enter your birthday a month, if and else with a judgment of the month is not your birthday month
the first method, datetime module acquisition time

 import datetime
 date=datetime.datetime.now() #获取当前时间
 # print(date.strftime('%Y-%m-%d')) #把当前时间格式化为可读懂的年月日
 r=date.strftime('%m') #把当前时间格式化为可读懂的年月日,只取月份
 print(r)
 t=input('请输入自己的生日月份：')
 if t==r:
     print('true')
 else:
     print('不是')

The second method, time module acquisition time

'''
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'''
 import time
 # date=time.time() #获取当前时间
 # print(date)
 # print(time.localtime(time.time()))#按固定格式显示当前时间
 # print(time.strftime('%Y-%m-%d')) #把当前时间格式化为可读懂的年月日
 # print(time.strftime('%Y-%m-%d',time.localtime(time.time()))) #把时间格式化为可读懂的年月日,后一个参数可省略
 # print(time.strftime('%m',time.localtime(time.time()))) #只取月儿份
 #t=time.strftime('%m',time.localtime(time.time()))#只取月儿份
 t=time.strftime('%m')#只取月儿份
 print(t)
 r=input('请输入自己的生日月份：')
 if t==r:
     print('true')
 else:
     print('不是')

5. Enter three letters: e, a, r, if input E, then the introduction of the cycle, if inputs a, execution continue, if the input r, then re-read the letter once, and printing, implemented using an infinite loop.

 while True:
     str = input('请输入三个字母：')
     if str=='r':
         print(str)
     if str=='a':
         continue
     if str=='e':
         break
     else:
         print('输入有误')

6. Enter three letters: e, a, r, if input E, then the loop is exited, if inputs a, execution continue, if the input r, then re-read the letter once, and print, only three letter input, repeat input the letter does not count.

'''
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'''
count = 0
for i in range(3):
    letter = input("send a letter%d："%i)
    if letter == 'e':
        break
    elif letter == 'a':
        continue
    elif letter == 'r':
        count += 1
        if count == 2:
            input("send a letter dddd：")

7. a string "abcdefg" is inserted into a list, each element of the letter representing the position of a list, for example:

["a","b","c","d","e","f","g"]
ls=["a","b","c","d","e","f","g"]
s="abcdefg"
lt=[]
#插入元素到后边
 for i in s :
     ls.extend(i)
 print(ls)

 for i in s:
     ls.append(i)
 print(ls)

#每个元素都插在第一个，或者说倒序插入列表前边
 for i in s:
     ls.insert(0,i)
 print(ls)

8. [ 'A', 'b', 'c', 'd', 'e', 'f', 'g'] This operation list, spell a character string "adg"

'''
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'''
 lis=['a','b','c','d','e','f','g']
 print(len(lis))
 t=lis[0]+lis[int(len(lis)/2)]+lis[-1]
 print(t)
 或
 print("".join(lis[::3]))

8 Python basis of interview exercises

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