To prove safety offer- backtracking - the range of motion of the robot -python

Title Description

A ground grid and m rows n columns. A robot moves from the grid coordinates 0,0, every time only left, right, upper, lower four directions a cell, but can not enter the row and column coordinates of the grid is greater than the sum of the number of bits k. For example, when k is 18, the robot can enter the box (35, 37), because 3 + 3 + 5 + 7 = 18. However, it can not enter the box (35, 38), because 3 + 3 + 5 + 8 = 19. Will the robot be able to reach the number of lattice?
# -*- coding:utf-8 -*-
class Solution:
    def __init__(self):
        self.count = 0
    def movingCount(self, threshold, rows, cols):
        # write code here
        arr = [[1 for i in range(rows)]for j in range(cols)]
        self.count_path(arr,0,0,threshold)
        return self.count
    def count_path(self,arr,i,j,k):
        if i<0 or j<0 or i>=len(arr) or  j>=len(arr[0]):
            return 
        tmpi = list(map(int, list(str(i))))
        tmpj = list(map(int, list(str(j))))
        if sum(tmpi)+sum(tmpj)>k or arr[i][j]!=1:
            return
        arr[i][j] = 0
        self.count+=1
        self.count_path(arr,i+1,j,k)
        self.count_path(arr,i-1,j,k)
        self.count_path(arr,i,j+1,k)
        self.count_path(arr,i,j-1,k)

 

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Origin www.cnblogs.com/ansang/p/11873447.html