1. The following grammar eliminate left recursion, and analyzed symbol string i * i + i
E -> E+T | T
T -> T*F | F
F -> (E) | i
solution:
(1) E-> TE '
E '-> + TE' | e
(2) T->FT'
T'->*FT'|ε
(3) F->(E)|i
2. materials page 1017 (2) (3)
(2) A->aABe|a
B->Bb|d
解:S->Aa|b S->SBa|b
A->SB
B->ab
(3) S->Aa|b
A->SB
B->ab
3. Workshop:
Seeking the following grammar FIRST set, FOLLOW sets and SELECT sets.
S->Ap
A->a |ε
A->cA
A->aA
① FIRST集:
First(S) = First(Ap) ={a,c}
First(a) = {a}
First(cA) = {c}
First(aA) = {a}
② FOLLOW集:
Follow
S->Ap
S->Bq
A->a
A->cA
B->b
B->dB
① FIRST集:
First(S1) = First(Ap) ={a,c}
First(S2) = First(Bq) ={b,d}
First(a) = {a}
First(cA) = {c}
First(b) = {b}
First(dB) = {d}
First(A) = {a,c} First(B) = {b,d}
② FOLLOW集: