Honestly greeners'garden digit reversal

#include<iostream>
#include<string>
using namespace std;
int main()
{    
    string s;
    char p=0;                     //放符号。
    int cnt=0;
    cin>>s;
    for(int i=0;i<s.size();i++)
    {
        if(s[i]>='0'&&s[i]<='9')
            cnt++;
        else
        { 
            P = S [I];
             BREAK ; 
        } 
    } 
    int X = CNT;   // X is the number of symbols in front of the (any) 
    cnt-- ;
     the while (S [CNT] == ' 0 ' && CNT> 0 ) / / 0 to remove the last of the foregoing figures, the leading zeros such that no flip. 
        CNT - ;
     for ( int I = CNT; I> = 0 ; i-- ) 
        COUT << S [I];
     IF (P == 0 ) // were treated unsigned%, other symbols.
        return  0 ; 
    the else 
    { 
        IF (P == ' % ' ) 
        { 
            COUT << P;
             return  0 ;     
        } 
        the else 
        COUT << P; 
    } 
    int m = s.size () - . 1 ;
     the while (S [X + . 1 ] == ' 0 ' && x <M- . 1 ) // 0 that x is not between the two ends to m, so that the number does not appear behind the leading zero flip. 
        the X- ++ ; // note that here the subscript relationship and numerical order.
    the while (S [m] == ' 0 ' && m> + X1)
        m--;
    for(int i=m;i>x;i--)
        cout<<s[i];
    return 0;            
}