Compilation of two (entry example)

 

1: character output

 LDA AX, BUffer: offset address of the associated address buffer was added to the AX register, hexadecimal 80868088 register 20-bit physical address

MOV AX, BUffer; Similarly, it will be the 16-bit buffer address into the AX register

SEGMENT the DATAS 
     STRS DB   ' the Hello World! ' , 13 is , 10 , ' $ ' 
     ; defines a string, reference is STRING, which is the address of the first character string. 
     ; DB is represented by each character in the string is one byte, plus 1 for each next time, the address offset plus 1. 
     ; 13 is CR carriage 
     ; 10 wrap the LF 
     ; $ as the end character string not the end of the output will be garbled 
DATAS eNDS 

STACKS SEGMENT Stack 

STACKS eNDS 

the ASSUME CS: CODE, DS: DATAS, SS: STACKS 
CODE SEGMENT 
main: 
    MOV AX, DATAS ; initialization code 
    MOV DS, AX ; initialization code
    The LEA   the DX, STRS ; the offset address register is loaded with data STRS 
    MOV the AH, . 9  ; . 9 of the output code 
    the INT 21H ; execute interrupt 
    MOV the AH, 4CH
     the INT 21H ;
 CODE ENDS 

End main

 2: sequence control

Sequence control is one of the core conditions constitute the program, particularly the main explain here:

Z = ((3X + Y-5) / 2 wherein X = 15HY = 10H

 

The DATAS SEGMENT
     ; defined Z = ((3X + Y- 5) / 2 wherein X-= 15H the Y = 10H 
    X-DW 15H 
    the Y DW 10H 
    ? The Z DW 
the DATAS ENDS 
the ASSUME the CS: CODE, the DS: the DATAS 
CODE SEGMENT 
main: 
    MOV AX, the DATAS ; initialization code 
    MOV the DS, AX ; initialization code 
    MOV AX, X-
     SHL AX, . 1 
    the ADD AX, X-
     the ADD AX, the Y
     the SUB AX, . 5 
    SAR AX, . 1 
    MOV the Z, AX
     the LEA the DX, the Z
     MOV the AH, 02H; display output
     INT 21H
    MOV AH,4CH
    INT 21H;
CODE ENDS

end main

 

3: Basic Process Control

Psw representatives need to understand the status register mean, here only need to focus on the zero flag ZF

 

 

 Where X is 2;

 

The DATAS SEGMENT
     ; defined X-= 2 
    X-DB 2 
    the Y DB? 
The DATAS ENDS 
the ASSUME the CS: CODE, the DS: the DATAS 
CODE SEGMENT 
main: 
    MOV AX, the DATAS ; initialization code 
    MOV the DS, AX ; initialization code 
    the CMP X-, 0 
    the JGE that Lable1 ; > = 0 
    MOV the Y, - . 1 
    the JMP Next
     that Lable1: 
    JZ lable2 ; = 0 
    MOV the Y, . 1 ;
     the JMP Next
     lable2: 
    MOV the Y,0 
    next:
    MOV AX,0
    MOV AH,4CH
    INT 21H;
CODE ENDS

end main