[Please dimensional phase inverter and those who do question] is common Pingyang sleeping lion Guo Fengjun inverting it in the hair of a post "[Please dimensional phase inverter and those who do common problem]," HTTP: // Tieba .baidu.com / the p-/ 5258171367 .
He raised a question in the post entitled:
I enemy machine track (assuming the same straight line flight), my machine radar signal transmission frequency f1 to the enemy at time t1, at time t2 is received by the frequency f2 is reflected by enemy radar signals. I beg machine and the relative velocity v of the enemy and the enemy of my machine and the distance L.
The following is a discussion of this question I answer and friends, I'm the king of K song in the quote in.
37th floor, this building is my answer:
Suppose the speed of light (electromagnetic wave velocity) with respect to the light (electromagnetic wave source) and the reflector constant is C,
I.e., the speed of light (electromagnetic wave speed) and the speed of light can be (electromagnetic wave source) and the reflector superposition.
I make the enemy machine in a straight line uniform motion, in my machine as a frame of reference, relative to my enemy machine speed v.
v = C - f2 * λ, λ is the wavelength of electromagnetic waves,
Because C = f1 * λ,
所以 v = f1 * k - f2 * l = (f1 - f2) * k,
Because C = f1 * λ,
Therefore, λ = C / f1,
Therefore, v = (f1 - f2) * λ = (f1 - f2) * C / f1,
I.e., v = ((f1 - f2) / f1) * C.
Provided electromagnetic waves transmitted from the aircraft and time of arrival is t hair dryer I, I reflected back from the enemy machine back to time t, equations can be obtained:
Fat C * t = (C - v) * t Press
sent back to t + t = t2 - t1
Solution of equations:
Fat C * t = (C - v) * (t2 - t1 - t Hair)
Fat C * t = (C - v) * t2 - (C - v) * t1 - (C - v) * t hair
Fat C * t + (C - v) * t hair = (C - v) * t2 - (C - v) * t1
C * t + C * t hair hair - v * t hair = (C - v) * (t2 - t1)
(2C - v) * t hair = (C - v) * (t2 - t1)
Hair t = (C - v) * (t2 - t1) / (2C - v)
Hair i.e. t = (C - v) * (t2 - t1) / (2C - v).
Two initial machine set distance L1, a distance of two planes L electromagnetic waves when reaching the enemy reaches the aircraft and,
L electromagnetic wave reaching the enemy = C * t hair
L1 = L wave reaches the enemy - v * t hair, v is the relative speed of the enemy machine I, above, has been obtained
L1 = C * t hair - v * t hair, t is the time sent from the electromagnetic wave reaching the enemy machine I, obtained immediately above
I.e. L1 = C * t hair - v * t hair, L1 is an initial distance required two machines.
40th floor
K Song King:
sxslwwd Pingyang sleeping lion Guo Fengjun
Your v = (f2 - f1) / (f2 + f1) * C,
My v = (f1 - f2) / f1 * C,
What about the practice?
When v is much smaller than C or C v close, you and I v v little difference, probably the biggest difference between the two is C / 2 in the v =,
This can also be used as an experiment designed to measure the speed of light.
East Xiao Wu Luming has Stygian boat people
Pingyang sleeping lion Guo Fengjun: Baidu, and consequently know
sxslwwd: to do this experiment, you must first create at least two aircraft flying speed c / 4, which is the flight speed is about 200000000m / s of the aircraft, and then on the fly, and then look at the results more realistic, wish you success!
sxslwwd: wrong, should be flying speed is about 75000000m / s of the plane, I guess you made out.
东方已晓: 回复 平阳睡狮郭峰君 :教课书上写的就是错的，你百度一下得到的也就是错的。在研究的状态下，只能自己去考察。对于时间是不是具有相对性的考察，关系到相对论能不能存在。百度出来的肯定都是说爱因斯坦相对论是真理。
东方已晓: 你这里说的不是测量光速的实验。测量光速的实验很多人都做过。只是地面上人的运动速度太低，测量出来的数值认为是测量误差，被忽视了而已。可以搜索《光速的测量》。
平阳睡狮郭峰君: 回复 东方已晓 :你得到的是正确的吗？
东方已晓: 对与错有别人去判定。我认为我得到的公式是正确的。频率差与波长的积就等于被测物体的运动速度（单向时）
47 楼
K歌之王 ：
东方已晓
他们 的 C + V 和 C - V 是 这么来的：
我机 向 敌机 射出 电磁波， 根据 “光速不变”， 电磁波 速度 相对于 敌机 是 C ， 以 我机 为 参照系 就是 C + V，
被 敌机 反射 回来 时， 因为 “光速不变”， 所以 反射回来 的 电磁波 速度 相对于 敌机 还是 C， 以 我机 为 参照系 就是 C - V，
于是， 就 产生了 f1 * (C + V) = f2 * (C - V) ，
这 其实 颇有 主观唯心主义 的 味道 。
这种解释 也是 相对论学派 对 迈克尔逊-莫雷 实验 的 解释 吧 ？
sxslwwd 吴露铭 燕山大学李子丰 黎耀天
杏园别居 csq567a 冥河乘船人 happyird 银河科学院