Python dictionary list sorted by the key values in the dictionary

Dictionary list sorted by the key values ​​in the dictionary

This is a relatively complex case ordering it, multiple nested, sorted according to certain rules.
The following JSON (Note: This is an item where the list):

[
    {
        "stat": { "question_id": 1339, "question__article__live": null, "question__article__slug": null, "question__title": "Team Scores in Football Tournament", "question__title_slug": "team-scores-in-football-tournament", "question__hide": false, "total_acs": 348, "total_submitted": 656, "frontend_question_id": 1212, "is_new_question": true }, "status": null, "difficulty": { "level": 2 }, "paid_only": true, "is_favor": false, "frequency": 0, "progress": 0 }, { "stat": { "question_id": 1337, "question__article__live": null, "question__article__slug": null, "question__title": "Design Skiplist", "question__title_slug": "design-skiplist", "question__hide": false, "total_acs": 748, "total_submitted": 1261, "frontend_question_id": 1206, "is_new_question": false }, "status": null, "difficulty": { "level": 3 }, "paid_only": false, "is_favor": false, "frequency": 0, "progress": 0 } ] 

 

list which is a dictionary, the dictionary or dictionaries, added in accordance with the frontend_question_idsort, provided two methods:

# 方法1，注：原列表为list1，排序后list2 
list2 = sorted(list1, key=lambda x : x['stat']['question_id']) # 方法2 list1.sort(key=lambda x: x["stat"]['question_id'])

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Reference:  Python sort a list, dictionary sort, dictionary sort list