Sort a list of dictionary with order of specific key

ExplodingGayFish :

I have a list of dict like this:

data = [{"uid": "a1", "name": "b1"}, 
        {"uid": "a3", "name": "b3"}, 
        {"uid": "a4", "name": "b4"},
        {"uid": "a5", "name": "b5"}]

Now I want to sort that list with the order of the uid field like this:

uid_order = ['a1', 'a5', 'a3', 'a4']

Which means the output should be:

[{"uid": "a1", "name": "b1"}, 
 {"uid": "a5", "name": "b5"},
 {"uid": "a3", "name": "b3"},
 {"uid": "a4", "name": "b4"}]

Of course, I can create a new empty list then use 2 for loops to check and add every element, but is there any elegant way (or better complexity) to do this?

Heap Overflow :

O(n) solution:

>>> [*map({d['uid']: d for d in data}.get, uid_order)]
[{'uid': 'a1', 'name': 'b1'},
 {'uid': 'a5', 'name': 'b5'},
 {'uid': 'a3', 'name': 'b3'},
 {'uid': 'a4', 'name': 'b4'}]

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