Analysis: known equation \ (F '(X) = \) \ (E ^ X (2x +. 3) \) \ (F + (X) \) is deformed into a \ (\ cfrac {f' ( x) -f (X)} E {X ^}. 3 = 2x + \) ,
Order \ (G (X) = \ {F cfrac (X)} E {X} ^ \) , then \ (g '(x) = \ cfrac {f' (x) -f (x)} {e ^ } X \) , then \ (G '(X). 3 = 2x + \) ,
The \ (G (X) = X ^ 2 + 3x + C \) , and because \ (F (0) =. 1 \) , then \ (g (0) = \ cfrac {f (0)} {e ^ 0} = 1 \) , then the clear \ (C = 1 \) ,
Therefore \ (G (X) = X ^ 2 + 3x +. 1 \) , and the inequality \ (f (x) <5e ^ x \) , ie \ (G (X) <. 5 \) , so \ (x ^ 2 . 1 + 3x + <. 5 \) ,
To give \ (X ^ 2 + 3x. 4-<0 \) , solve for \ (-. 4 <X <. 1 \) , was chosen \ (A \) .