Questions surface: http://codeforces.com/contest/311/problem/B
Luogu questions surface: https://www.luogu.com.cn/problem/CF311B
Optimization slope DP
We set t [i] = the end time of kittens - from 1 to place it in the distance.
Since when is starting to let the cat can not wait.
To the best trip we definitely do not want a wait.
His sort, then that can be received on a k cat breeder picked up after all this time just to receive between cats cat i.
Around a bit.
Then dp formula can be introduced.
f [i] [j] = min (f [i] [j], f [i -1] [k] + T [j] * (jk) - (S [j] -s [k])).
Removed min.
f[i-1][k]+s[k]=t[j]*k+f[i][j]-t[j]*j+s[j]
Set to y = kx + b form.
Then k is t [j], x is k, y is in front of that a lot.
You will be happy to maintain the lower slope of the convex hull is optimized.
code show as below:
#include<bits/stdc++.h> #define ll long long using namespace std; const int maxn=1e5+10; ll f[110][maxn],g[maxn],s[maxn],t[maxn]; int n,m,p,d[maxn],q[maxn]; int main() { scanf("%d%d%d",&n,&m,&p); for(int i=2;i<=n;i++){ scanf("%d",&d[i]);d[i]+=d[i-1]; } for(int i=1;i<=m;i++){ int x,y;scanf("%d%d",&x,&y); t[i]=y-d[x]; } sort(t+1,t+1+m); for(int i=1;i<=m;i++) s[i]=s[i-1]+t[i]; memset(f,0x3f,sizeof(f)); f[0][0]=0; for(int i=1;i<=p;i++){ for(int j=1;j<=m;j++) g[j]=f[i-1][j]+s[j]; int l=1,r=1;q[1]=0; for(int j=1;j<=m;j++){ while(l<r && g[q[l+1]]-g[q[l]]<=t[j]*(q[l+1]-q[l])) l++; f[i][j]=min(f[i-1][j],g[q[l]]+t[j]*(j-q[l])-s[j]); if(g[j]>=0x3f3f3f3f3f3f3f3fll) continue; while(l<r && (g[j]-g[q[r]])*(q[r]-q[r-1])<=(g[q[r]]-g[q[r-1]])*(j-q[r])) r--; q[++r]=j; } } printf("%lld\n",f[p][m]); return 0; }