Title description:
Given n integers, find the continuous sub-array with the largest average and length k, and output the largest average.
Hint:
1 <= k <= n <= 30,000.
The given data range [-10,000, 10,000].
Example:
Input: [1,12,-5,-6,50,3], k = 4
Output: 12.75
Explanation: Maximum average (12-5-6+50)/4 = 51/4 = 12.75
code show as below:
class Solution {
public double findMaxAverage(int[] nums, int k) {
int n = nums.length;
int left = 0, right = 0;
double ans = 0;
for (int i = 0; i < k; i++) {
ans += nums[i];
}
double m = ans / k;
while (right < n) {
if (right - left == k) {
ans = ans - nums[left] + nums[right];
left++;
}
right++;
m = Math.max(m, ans / k);
}
return m;
}
}
Results of the:
