Transfer: https://blog.csdn.net/lql0716/article/details/52910812
numpy.power(x1, x2)
Each element of the array of n - th. x2 may be digital, or an array, but the number of columns to be the same as x1 and x2.
>>> x1 = range(6)
>>> x1
[0, 1, 2, 3, 4, 5]
>>> np.power(x1, 3)
array([ 0, 1, 8, 27, 64, 125])
1
2
3
4
5
>>> x2 = [1.0, 2.0, 3.0, 3.0, 2.0, 1.0]
>>> np.power(x1, x2)
array([ 0., 1., 8., 27., 16., 5.])
1
2
3
>>> x2 = np.array([[1, 2, 3, 3, 2, 1], [1, 2, 3, 3, 2, 1]])
>>> x2
array([[1, 2, 3, 3, 2, 1],
[1, 2, 3, 3, 2, 1]])
>>> np.power(x1, x2)
array([[ 0, 1, 8, 27, 16, 5],
[ 0, 1, 8, 27, 16, 5]])
---------------------
作者：jason_ql
来源：CSDN
Original: https: //blog.csdn.net/lql0716/article/details/52910812 utm_source = copy?
Disclaimer: This article is a blogger original article, reproduced, please attach Bowen link!