Topics requirements:
Solution one:
Directly sort descending order, taking the k-th
var findKthLargest = function (nums, k) { nums.sort((a, b) => { return b - a }); return nums[k - 1]; };
Solution two (to optimize performance):
Using bubble sort, taking the reciprocal of the k-th
var findKthLargest = function (nums, k) { for (var i = nums.length - 1; i > nums.length - k - 1; i--) { var temp; for (var j = 0; j < i; j++) { if (nums[j] > nums[j + 1]) { temp = nums[j + 1]; nums[j + 1] = nums[j]; nums[j] = temp; } } } return nums[nums.length - k]; };