Chapter 3 C Hemopurification fifth edition exercises answers

#include <stdio.h> 
#include <math.h> int main () {
     // requirements: v5p80: known p = (1 + r) ^ n, n = 10 when required, r is the number points a float R & lt = 0.07 ;
     a float P = ( a float ) POW ( . 1 + R & lt, 10 ); 
    the printf ( " P:. %% 0F% \ n- " , P * 100 );
     return 0 ; 
}


     

 

. 1 #include <stdio.h>
 2 #include <math.h>
 . 3  
. 4  int main () {
 5      // interest count
 6      @ a deposit of 5 years; 1000 * (. 1 + n-R & lt *) 
. 7      a float SUM1 = 1000 * ( 1 + 5 * 0.03 );
 8      // preexisting biennial, and then deposit principal and interest after the expiration of 3 years; 
. 9      a float SUM2 = 1000 * ( 1 + 2 * 0.021 ) * ( 1 + 3 * 0.0275 );
 10      // pre-existing three-year period, then deposit the biennium
. 11      a float sum3 = 1000 * ( . 1 + . 3 * 0.0275 ) * ( . 1 + 2 * 0.021 );
 12 is      // save 5 times for 5-year 
13 is      a float SUM4 = 1000 * POW ( . 1 + 0.015 , 5 );
 14      // survival of each of quarter 
15      a float sum5 = 1000 * POW ( . 1 + 0.0035 / . 4 , . 4 * . 5 );
 16  //    1150.00
17 //    1127.96
18 //    1127.96
19 //    1077.28
20 //    1017.65
21     printf("%.2f\n%.2f\n%.2f\n%.2f\n%.2f\n", sum1, sum2, sum3, sum4, sum5);
22     return 0;
23 }

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