Article Directory
1. Multiple choice questions
1—5 CACBB
6—10 CDBBB
11—15 ADCCB
16—20 DCCBB
Two, fill in the blanks
- (a!=b)||(a<=c)
- (x>20)&&(x<30)||(x<-100)
- 0
- 1
- 1
if((x%3==0) && (x%7==0) )
Three, programming questions
- Enter a positive integer from the keyboard to determine whether it is a multiple of 3 and 5, if it is, enter yes, otherwise output no
#include<stdio.h>
int main()
{
int x;
printf("请输入一个正整数");
scanf("%d",&x);
if((x%3==0)&&(x%5==0))
printf("yes");
else
printf("no");
return 0;
}
- Write a program, enter the length of the three sides of the triangle, and find the area. Note: The sum of any two sides of the triangle must be greater than the third side. For unreasonable side length input, an error message is required.
#include<stdio.h>
#include<math.h>
int main()
{
double a,b,c,p,s;
printf("输入三角形的3个边长");
scanf("%lf%lf%lf",&a,&b,&c);
if((a+b>c)&&(a+c>b)&&(b+c>a)){
p=(a+b+c)/2;
s=sqrt(p*(p-a)*(p-b)*(p-c));
}
else{
printf("输入边长不合理");
return 0;
}
printf("%0.2lf",s);
return 0;
}
- Write a program according to the following piecewise function, input an x value, and output the corresponding y value
#include<stdio.h>
int main()
{
float x,y;
printf("请输入x值");
scanf("%f",&x);
if((x>-5)&&x<0){
y=x-1;
}
else if(x==0){
y=x;
}
else if(x>0&&x<8){
y=x+1;
}
else{
y=10;
}
printf("%f",y);
return 0;
}
- Input a character from the keyboard, if it is a lowercase letter, it will be converted to uppercase and output, if it is a capital letter, it will be converted to lowercase and output, and other characters will be output as they are
#include<stdio.h>
int main()
{
char a;
a=getchar();
if(a>='a'&&a<='z'){
a=a-32;
putchar(a);
}
else if(a>='A'&&a<='Z'){
a=a+32;
putchar(a);
}
else{
putchar(a);
}
return 0;
}
- Input 3 integers from the keyboard to the variables a, b, c, and sort these 3 numbers from small to large, a is the smallest number, and c is the largest number
#include<stdio.h>
int main()
{
int a,b,c,t=0;
scanf("%d%d%d",&a,&b,&c);
if(a>b){
t=a;
a=b;
b=t;
}
if(a>c){
t=c;
c=a;
a=t;
}
if(b>c){
t=b;
b=c;
c=t;
}
printf("a=%d,b=%d,c=%d",a,b,c);
return 0;
}
- Enter a 3-digit number to determine whether it is a daffodil number, and a prompt will be given when the input data is incorrect. The number of daffodils is a three-digit number, and the sum of the cubes of the digits is equal to the number itself.
#include<stdio.h>
int main()
{
int x,g,s,b;
scanf("%d",&x);
if(x>999||x<0){
printf("输入数据不正确");
return 0;
}
g=x%10;
s=x/10%10;
b=x/100;
if(x==(g*g*g+s*s*s+b*b*b)){
printf("%d是水仙花数",x);
}
else{
printf("%d不是水仙花数",x);
}
return 0;
}
- Enter the values of 3 integers a, b, and c from the keyboard to find the root of the quadratic equation ax*x+bx+c=0 (a!=0), and the calculation result retains two decimal places
#include<stdio.h>
#include<math.h>
int main()
{
int a,b,c,s,x1,x2;
scanf("%d%d%d",&a,&b,&c);
if(a==0){
printf("输入数据错误");
}
s=b*b-4*a*c;
if(s>0){
x1=((-b)+sqrt(s))/(2*a);
x2=((-b)-sqrt(s))/(2*a);
printf("方程有2个解：x1=%d,x2=%d",x1,x2);
}
else if(s==0){
printf("方程有1个解：x=%d",(-b)/(2*a));
}
else{
printf("方程无解");
}
return 0;
}
#include<stdio.h>
int main()
{
int year;
double sum;
printf("输入本金与期限");
scanf("%lf%d",&sum,&year);
if(year==8){
printf("金额：%0.2lf,期限：%d",sum+sum*0.0032,year);
}
else if(year==5){
printf("金额：%0.2lf,期限：%d",sum+sum*0.00275,year);
}
else if(year==3){
printf("金额：%0.2lf,期限：%d",sum+sum*0.00245,year);
}
else if(year==2){
printf("金额：%0.2lf,期限：%d",sum+sum*0.00230,year);
}
else if(year==1){
printf("金额：%0.2lf,期限：%d",sum+sum*0.00215,year);
}
else{
printf("不是上述年限，请重新输入");
}
return 0;
}
#include<stdio.h>
int main()
{
int year;
double sum;
printf("输入本金与期限");
scanf("%lf%d",&sum,&year);
switch(year){
case 8: sum=sum+sum*0.0032;break;
case 5: sum=sum+sum*0.00275;break;
case 3: sum=sum+sum*0.00245;break;
case 2: sum=sum+sum*0.00230;break;
case 1: sum=+sum*0.00215;break;
default :printf("不是上述年限，请重新输入"); return 0;
}
printf("金额：%0.2lf,期限：%d",sum,year);
return 0;
}
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