The meaning of problems: given N * M matrix '*' can be represented by the '#' can not be expressed, it is to find two paths from [1,1] to [N, M] to, in addition to starting and ending points such that, there is no intersection.
Ideas: no idea, it is bare title. Lindström-Gessel-Viennot lemma
a to b, c to d, the intersection of the two paths there is no program number = w [a, b] * w [c, d] -w [a, d] * w [b, c];
#include<bits/stdc++.h> #define rep(i,a,b) for(int i=a;i<=b;i++) const int maxn=3010; const int Mod=1e9+7; int mp[maxn][maxn],N,M,res; char c[maxn][maxn]; int solve(int sx,int sy,int tx,int ty) { memset(mp,0,sizeof(mp)); mp[sx][sy]=1; rep(i,1,N) rep(j,1,M) { if(c[i][j]=='#') continue; if(c[i-1][j]=='.') (mp[i][j]+=mp[i-1][j])%=Mod; if(c[i][j-1]=='.') (mp[i][j]+=mp[i][j-1])%=Mod; } return mp[tx][ty]; } int main() { scanf("%d%d",&N,&M); rep(i,1,N) scanf("%s",c[i]+1); res=1LL*solve(1,2,N-1,M)*solve(2,1,N,M-1)%Mod-1LL*solve(1,2,N,M-1)*solve(2,1,N-1,M)%Mod; if(res<0) res+=Mod; printf("%d\n",res); return 0; }