Although I have not been in Los Valley
However, I had a (funny in CF
Subject to the effect
To the equation \ (Ax of + By + C = 0 \) . Wherein \ (A \) , \ (B \) , \ (C \) is known, find \ (X \) , \ (Y \) .
\(Idea\)
Expand the template title Euclidean algorithm.
The algorithm determined linear equation \ (Ax + By = gcd ( A, B) \)
Then, this equation can be converted:
\[Ax + By = gcd(A, B)\]
\[\to Ax + By = -\frac{C}{z}, -\frac{C}{z}= gcd(A, B)\]
\ [\ To Ax \ AST + By \ AST = C \]
Where \ (the X-\) , \ (the y-\) may be obtained by expanding the Euclidean algorithm,
Then, we simply requires the \ (Z \) , and \ (Z = - \ {C} {FRAC GCD (A, B)} \) ;
Therefore, the final answer \ (X = X \ AST - \ FRAC {C} {GCD (A, B)} \) , \ (Y = Y \ AST - \ FRAC {C} {GCD (A, B)} \ ) ;
_____
given below template to expand Euclid
inline int ecgcd(int a,int b,int &x,int &y){
if(!b) {x=1; y=0; return a;}
int d=exgcd(b,a%b,x,y);
int z=x; x=y; y=z-y*(a/b);
return d;
}
\ (AC \) program to write their own