Given two binary nonempty s and t, and the test is included in s t subtrees having the same structure and the node values. s of a subtree including all the descendants of a node and the node s. s can be seen as its own subtree.
Example 1:
given tree s:
3
/ \
45
/ \
12
given tree t:
4
/ \
12
returns true, since t and s in a sub-tree nodes have the same structure and values.
Example 2:
given tree s:
3
/ \
45
/ \
12
/
0
given tree t:
4
/ \
12
returns false.
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: void dfs_s(TreeNode* root, string &res){ if(!root){ res+='#'; return; } res+='?'+to_string(root->val); dfs_s(root->left, res); dfs_s(root->right, res); } bool isSubtree(TreeNode* s, TreeNode* t) { string ss,tt; dfs_s(s,ss); dfs_s(t,tt); int n=tt.size(); vector<int>ne(n); int j=-1; ne[0]=-1; for(int i=1;i<n;i++){ while(j>-1&&tt[i]!=tt[j+1])j=ne[j]; if(tt[i]==tt[j+1])j++; ne[i]=j; } j=-1; for(int i=0;i<ss.size();i++){ while(j>-1&&ss[i]!=tt[j+1])j=ne[j]; if(ss[i]==tt[j+1])j++; if(j==n-1)return true; } return false; } };