First, with regard to the number of Cattleya
Cattleya number is a number of classical composition, often in a variety of calculations, which is the first few: 1, 2, 5, 14, 42, 132, 429, 1430, 4862, 16796, 58786, 208012, 742900 , 2674440, 9694845, 35357670, 129644790, 477638700, 1767263190, 6564120420, 24466267020, 91482563640, 343059613650, 1289904147324, 4861946401452, ...
Second, the general formula for the number of Cattleya
Cattleya number satisfy the following properties:
So that h (0) = 1, h (1) = 1, catalan a number satisfying the recurrence formula. h (n) = h (0 ) * h (n-1) + h (1) * h (n-2) + ... + h (n-1) h (0) (n> = 2). That is, if this form can be formulated into the above number is the number of Cattleya .
Of course, such a recursive formula above is too cumbersome, so mathematicians and obtained a general term formula can be quickly calculated. H (n-) = C (2N, n-) -C (2N, n-+. 1) (n-= 0,1,2, ...) . This formula can also be more simply obtained into H (n-) = C (2N, n-) / (n-+. 1) . After a formula can come through a few simple calculations by the previous formula, you can try to pick up a pen, a minute or two can get.
Detailed look https://blog.csdn.net/wookaikaiko/article/details/81105031
#include<cstdio> #include<cstring> #include<algorithm> using namespace std; typedef long long ll; int n; ll ans[100]={1,1}; int main() { for(int i=2;i<=32;i++) { for(int j=0;j<i;j++) { ans[i]+=ans[j]*ans[i-j-1]; } } while(scanf("%d",&n)&&n) { printf("%lld\n",ans[n]); } return 0; }
Uses: parenthesized
The stack order of the convex polygon triangulation given binary search tree nodes n of the number of matching right parenthesis
I do not know what these are, ah, Baidu investigation;