Disclaimer: This article is a blogger original article, shall not be reproduced without the bloggers allowed. https://blog.csdn.net/iov3Rain/article/details/90242918
Title Description
There is a row over the array of strings sequence, but there are inserted some empty string, design an algorithm to identify the location of a given string. Find a part of the complexity of the algorithm should log level.
Given an array of string str, while a given array size n and X need to find a string, the string return to the position (zero-position).
Test sample:
["a","b","","c","","d"],6,"c"
Returns: 3
Modified binary search, the mid reset generation method.
starting from the high to mid to low down position, the first string is not empty
class Finder {
public:
int findString(vector<string> str, int n, string x) {
// write code here1
int low = 0;
int high = str.size() - 1;
while(low < high)
{
int mid;
for(mid = high; mid >= low; --mid)
if(str[mid] != "")
break;
if(str[mid] < x)
{
low = mid + 1;
}
else if(str[mid] > x)
{
high = mid - 1;
}
else
{
return mid;
}
}
return -1;
}
};