Given a positive integer, output its complement. Complement is a negation of the binary number.
note:
给定的整数保证在32位带符号整数的范围内。
你可以假定二进制数不包含前导零位。
Example 1:
Input: 5
Output: 2
Explanation: 5 is represented by binary 101 (no leading zero bits), which is the complement of 010. So you need to output 2.
Example 2:
Input: 1
Output: 0
Explanation: 1 is represented by a binary 1 (no leading zero bits), which complement is 0. So you need to output 0.
class Solution {
public int findComplement(int num) {
if(num > Integer.MAX_VALUE / 2){//大于MAX_VALUE的一半时,位数已经与MAX_VALUE一样,可以用MAX_VALUE异或
return num ^ Integer.MAX_VALUE;
}
//拿到刚好比num大的2的倍数
int i = 1;
while(i <= num){
i = i * 2;
}
//拿到的数,减一刚好是与num位置相等的所有二进制为1的数
i -= 1;
return i ^ num;
}
// 8 1000 | 5 101
// 16 10000 | 8 1000
// 15 1111 | 7 111
// 8 ^ 15 0111 | 5 ^ 7 010
}