In this logic problem collecting

Two water bottles, a water can be installed 5L, 6L can be installed a water, how to make one of them equipped with 3L water?

First, the 5L filled with (now there are pot pot 5L 5L, 6L of no water) second, down to the inside of the 5L and 6L (now the pot 5L no water, there 5L 6L pot ) third, again filled with pot 5L (5L now have pot 5L, 5L and 6L pot there) fourth, then 5L pot of water to pour in 6 inside (inside 6L is now full, inside there is a 5L 4L) fifth, the 6L pot of water drained (now 5L water pot 4L, 6L pot of no water) sixth, the pot of water poured into it full-5L and 6L (now 5L the pot without water, there 6L pot 4L water) seventh, the 5L pot filled (there are now 5L 5L water pot, pot 6L has 4L water) eighth, the pot of water 5L pour into the pot just turned the pot 6L and 6L (pot has done 5L 3L water, there 6L 6L pot of water)

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Origin www.cnblogs.com/tzxy/p/11002678.html