Subject description:
Given a binary search tree, please find the first k smaller nodes therein. For example, (5,3,7,2,4,6,8), the numerical values according to the third junction point is 4 summary.
Analysis of ideas:
According to the particularity of binary search tree, we preorder sequence is an ordered sequence it generates, so in order to traverse the first point is the first K K small nodes.
Code:
import java.util.*;
/*
public class TreeNode {
int val = 0;
TreeNode left = null;
TreeNode right = null;
public TreeNode(int val) {
this.val = val;
}
}
*/
public class Solution {
/*
用非递归的方式实现中序遍历
*/
TreeNode KthNode(TreeNode pRoot, int k)
{
if(pRoot==null||k<0)
return null;
TreeNode pNode=pRoot;
Stack<TreeNode>s=new Stack<>();
int count=0;
while(pNode!=null||!s.isEmpty()){
while(pNode!=null){
s.push(pNode);
pNode=pNode.left;
}
if(!s.isEmpty()){
pNode=s.pop();
count++;
if(count==k)
return pNode;
pNode=pNode.right;
}
}
return null;
}
}