Use shift operation into binary to decimal and hexadecimal string output

Prototype:

1  // turn binary 
2  char * ConvertTo2String ( Long Number);
 . 3  // convert hexadecimal 
. 4  char * ConvertTo16String ( Long Number);

 

Ideas:

　　Binary conversion is very simple, two-step operation to complete,

       　　1: number for the recycling and the operation of the digital bits and a left 31-i (i = {0,31}) bits (high-order), and,

　　　　   2: the results then just right 31-i (i = {0,31}) obtained per one bit is 0 or 1,

　　This was every bit, and then these bits makes up the string on the OK!

 1 char *ConvertTo2String(long number)
 2 {
 3      char *output = NULL;
 4      output = (char*)malloc(33);    //include '\0'
 5       
 6      int i = 0;
 7      for(;i<32;i++)
 8      {
 9          output[i] = number & (1<<31-i);
10          output[i] = output[i] >> 31-i;
11          output[i] = (output[i] == 0) ? '0' : '1';
12      }
13      output[i] = '\0';
14      return output
15 }

 

 

Converts a hexadecimal trouble that we have to consider the case of letters

 1 char * ConvertTo16String(long number)
 2 {
 3     char *output= NULL;
 4     char *temp = NULL;
 5  
 6     output= (char*) malloc(11);
 7  
 8     output[0] = '0';
 9     output[1] = 'x';
10     output[10] = '\0';
11     + = Output TEMP 2 ;
 12 is   
13 is      for ( int I = 0 ; I < . 8 ; I ++ )
 14      {
 15          TEMP [I] = ( char ) (<< Number 4 * I >> 28 );     // first left 4 * i, then the right 28, each treatment 4 
16          TEMP [I] = TEMP [I]> = 0 TEMP [I]:? TEMP [I] + 16 ;     // to convert letters a ~ F prepare 
. 17          TEMP [I] = TEMP [I] < 10 ? TEMP [I] + 48 : TEMP [I] + 55 ;    // turn letters
18     }
19     
20     return output;
21 }