filter() function in python

        In Python, the `filter()` function is a built-in function that accepts a function and an iterable object as arguments and returns an iterator containing elements that satisfy the function's conditions. Its function is to filter the elements in the iterable object according to the conditions of the function and return an iterator containing elements that meet the conditions.
The following is the syntax of the `filter()` function:
filter(function, iterable)
- `function`: Function used to filter elements. The function should return a boolean value, either `True` or `False`.
- `iterable`: an iterable object, which can be a list, tuple, set, etc.

Here is an example of using the `filter()` function to filter out even numbers in a list:

numbers = [1, 2, 3, 4, 5, 6]
result = filter(lambda x: x % 2 == 0, numbers)
print(list(result))
输出:
[2, 4, 6]

        In the above example, we used an anonymous function `lambda x: x % 2 == 0` as the first parameter of the `filter()` function. This function determines whether the passed parameter `x` is an even number. We then pass the `numbers` list as the second parameter to the `filter()` function, which filters out the even numbers in the list based on the function's conditions and returns an iterator containing the elements that satisfy the conditions. Finally, we convert the iterator to a list and print it.
        In summary, the `filter()` function can filter the elements in an iterable object based on the function's conditions and return an iterator containing elements that meet the conditions. It is a concise and efficient way to filter iterable objects.

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Origin blog.csdn.net/weixin_49786960/article/details/131812337