[Lanqiao Cup 2023 Country B] Number of Geminis
Test question B: Gemini number
【Problem Description】
If a positive integer xxx can be expressed asp 2 × q 2 p^2 \times q^2p2×q2 , whereppp、 q q q is a prime number andp ≠ qp \neq qp=q , thenxxx is
a "gemini number". Please calculate the interval[2333, 23333333333333] [2333, 23333333333333][2333,How many "gemini numbers" are there in 23333333333333 ] ?
Sieve of Ehrlich + brute force enumeration
#include<bits/stdc++.h>
using namespace std;
int main()
{
int d=sqrt(23333333333333);
cout<<d<<endl; //4830458
vector<__int128> primes;
vector<bool> st(5000010);
st[0]=st[1]=1;
for(int i=2;i<=5000000;i++)
{
if(st[i]==0) primes.push_back(i);
for(int j=0;j<primes.size()&&primes[j]<=5000000/i;j++)
{
st[primes[j]*i]=true;
if(i%primes[j]==0) break;
}
}
auto a=primes;
int ans=0;
for(int i=0;i<a.size();i++)
for(int j=i+1;j<a.size();j++)
{
if(a[i]*a[i]*a[j]*a[j]<2333)
continue;
if(a[i]*a[i]*a[j]*a[j]>23333333333333)
break;
ans++;
}
cout<<ans;//947293
return 0;
}